Match each statement with the example subnet and wildcard that it describes. (Not all options are used.)

IT Questions BankCategory: CCNAMatch each statement with the example subnet and wildcard that it describes. (Not all options are used.)
Match each statement with the example subnet and wildcard that it describes. (Not all options are used.) 1ITExamAnswers Staff asked 1 year ago

Question:
Match each statement with the example subnet and wildcard that it describes. (Not all options are used.)

Match each statement with the example subnet and wildcard that it describes. (Not all options are used.) 2

Answer

Match each statement with the example subnet and wildcard that it describes. (Not all options are used.) 3

Place the options in the following order:
192.168.15.65 255.255.255.240 ==> the first valid host address in a subnet
192.168.15.144 0.0.0.15 ==> subnetwork address of a subnet with 14 valid host addreses
host 192.168.15.2 ==> all IP address bits must match exactly
192.168.5.0 0.0.3.255 ==> hosts in a subnet with SM 255.255.252.0
192.168.3.64 0.0.0.7 ==> address with a subnet 255.255.255.248

Explanation: Converting the wildcard mask 0.0.3.255 to binary and subtracting it from 255.255.255.255 yields a subnet mask of 255.255.252.0.
Using the host parameter in a wildcard mask requires that all bits match the given address.
192.168.15.65 is the first valid host address in a subnetwork beginning with the subnetwork address 192.168.15.64. The subnet mask contains 4 host bits, yielding subnets with 16 addresses.
192.168.15.144 is a valid subnetwork address in a similar subnetwork. Change the wildcard mask 0.0.0.15 to binary and subtract it from 255.255.255.255, and the resulting subnet mask is 255.255.255.240.
192.168.3.64 is a subnetwork address in a subnet with 8 addresses. Convert 0.0.0.7 to binary and subtract it from 255.255.255.255, and the resulting subnet mask is 255.255.255.248. That mask contains 3 host bits, and yields 8 addresses.

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