Which of the following is the prefix for address 2000:0000:0000:0005:6000:0700: 0080:0009, assuming a mask of /64?
- 2000::5::/64
- 2000::5:0:0:0:0/64
- 2000:0:0:5::/64
- 2000:0:0:5:0:0:0:0/64
Explanation: The /64 prefix length means that the last 64 bits, or last 16 digits, of the address should be changed to all 0s. That process leaves the unabbreviated prefix as 2000:0000:0000:0005:0000:0000:0000:0000. The last four quartets are all 0s, making that string of all 0s be the longest and best string of 0s to replace with ::. After removing the leading 0s in other quartets, the answer is 2000:0:0:5::/64.
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