What is obtained when ANDing the address 192.168.65.3/18 with its subnet mask?
- 192.168.0.0
- 192.168.16.0
- 192.168.32.0
- 192.168.64.0
Explanation: The value of the IP address 192.168.65.3 in binary is 11000000.10101000.01001110.00000011. The value of the subnet mask in binary is 11111111.11111111.11000000.00000000. When ANDing the two, the result is 11000000.10101000.01000000.00000000, which in turn converts into 192.168.64.0.
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