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1. What happens if you try to compile and run this program?
#includeint main(void) { int i, j, k; i = -1; j = 1; if(i) j--; if(j) i++; k = i * j; printf("%d",k); return 0; }
- the program outputs2
- the program outputs -1
- the program outputs 1
- the program outputs 0
2. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i, j, k;
i = 0;
j = 0;
if(j)
j--;
else
i++;
if(i)
i--;
else
j++;
k = i + j;
printf("%d",k);
return 0;
}- the program outputs 2
- the program outputs -1
- the program outputs 0
- the program outputs 1
3. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i, j, k;
i = 2;
j = 3;
if(j)
j--;
else if(i)
i++;
else
j++;
if(j)
i--;
else if(j)
j++;
else
j = 0;
k = i + j;
printf("%d",k);
return 0;
}- the program outputs 3
- the program outputs 1
- the program outputs 2
- the program outputs 0
4. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
double x = -.1;
int i = x;
printf("%d",i);
return 0;
}- the program outputs -0.100000
- the program outputs -1
- the program outputs 0.100000
- the program outputs 0
5. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
float x,y;
int i,j;
x = 1.5; y = 2.0;
i = 2; j = 3;
x = x * y + i / j;
printf("%f",x);
return 0;
}- the program outputs 3.000000
- the program outputs 2.000000
- the program outputs 1.000000
- the program outputs 0.000000
6. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
float x,y;
int i,j;
x = 1.5; y = 2.0;
i = 2; j = 4;
x = x * y + (float)i / j;
printf("%f",x);
return 0;
}- the program outputs 2.000000
- the program outputs 3.000000
- the program outputs 4.000000
- the program outputs 3.500000
7. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i;
i = 1;
while(i < 16)
i *= 2;
printf("%d",i);
return 0;
}- the program outputs 32
- the program outputs 4
- the program outputs 16
- the program outputs 8
8. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i, j;
i = 1; j = 1;
while(i < 16) {
i += 4;
j++;
}
printf("%d",j);
return 0;
}- the program outputs 4
- the program outputs 7
- the program outputs 5
- the program outputs 6
9. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 7, j = i - i;
while(i) {
i /= 2;
j++;
}
printf("%d",j);
return 0;
}- the program outputs 3
- the program outputs 2
- the program outputs 1
- the program outputs 0
10. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 7, j = i - i;
while(!i) {
i /= 2;
j++;
}
printf("%d",j);
return 0;
}- the program outputs 1
- the program outputs 0
- the program outputs 2
- the program outputs 3
11. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i, j = 1;
for(i = 11; i > 0; i /= 3)
j++;
printf("%d",j);
return 0;
}- the program outputs 3
- the program outputs 5
- the program outputs 4
- the program outputs 2
12. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i, j = 0;
for(i = 0; !i ; i++)
j++;
printf("%d",j);
return 0;
}- the program outputs 1
- the program outputs 3
- the program outputs 0
- the program outputs 2
13. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = -2;
for(;;) {
i *= 3;
j++;
if(i > 30)
break;
}
printf("%d",j);
return 0;
}- the program outputs 3
- the program outputs 1
- the program outputs 0
- the program outputs 2
14. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = -2, k;
k = (i >= 0) && (j >= 00) || (i <= 0) && (j <= 0);
printf("%d",k);
return 0;
}- the program outputs 3
- the program outputs 2
- the program outputs 0
- the program outputs 1
15. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = -2, k;
k = (i >= 0) || (j >= 00) && (i <= 0) || (j <= 0);
printf("%d",k);
return 0;
}- the program outputs 1
- the program outputs 3
- the program outputs 0
- the program outputs 2
16. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = -2, k;
k = !(i >= 0) || !(j >= 00) && !(i <= 0) || !(j <= 0);
printf("%d",k);
return 0;
}- the program outputs 0
- the program outputs 1
- the program outputs 2
- the program outputs 3
17. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = 0, k;
k = i & j;
k |= !!k;
printf("%d",k);
return 0;
}- the program outputs 1
- the program outputs 2
- the program outputs 0
- the program outputs 3
18. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = 0, k;
k = !i | j;
k = !k;
printf("%d",k);
return 0;
}- the program outputs 2
- the program outputs 0
- the program outputs 1
- the program outputs 3
19. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 1, j = 0, k;
k = (i ^ j) + (!i ^ j) + (i ^ !j) + (!i ^ !j);
printf("%d",k);
return 0;
}- the program outputs 1
- the program outputs 2
- the program outputs 3
- the program outputs 0
20. What happens if you try to compile and run this program?
#include <stdio.h>
int main(void) {
int i = 0, j = 1, k;
k = i << j + j << i;
printf("%d",k);
return 0;
}- the program outputs 0
- the program outputs 2
- the program outputs 3
- the program outputs 1
