Programming Essentials in C: Chapter 8 Assignment (CLA) Exam Answers

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1. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA	-2 
    int main(void) { 
        int i = -1; 
        i += ALPHA; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -2
  • the program outputs -3
  • the program outputs 0

2. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA	-1+2 
    int main(void) { 
        int i = -1; 
        i += ALPHA; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -3
  • the program outputs -2
  • the program outputs 0
  • the program outputs -1

3. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA	-1-2 
    int main(void) { 
        int i = -1; 
        i = i * ALPHA; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -2
  • the program outputs -3
  • the program outputs 0

4. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA	(-1-2) 
    int main(void) { 
        int i = -1; 
        i = -i * ALPHA; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs 0
  • the program outputs -3
  • the program outputs -1

5. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA	-1 
    #define   BETA	     - ALPHA 
    int main(void) { 
        int i = ALPHA + BETA * ALPHA * BETA; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -3
  • the program outputs -2
  • the program outputs -1
  • the program outputs 0

6. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA(x)	-x 
    int main(void) { 
        int i = ALPHA(2-1); 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs 0
  • the program outputs -2
  • the program outputs -3

7. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA(x)	2*-x 
    int main(void) { 
        int i = ALPHA(1-1); 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs -3
  • the program outputs -1
  • the program outputs 0

8. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA(x)	2*-x 
    int main(void) { 
        int i = ALPHA((1-1)); 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -2
  • the program outputs -3
  • the program outputs 0

9. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA(x,y)	x##2-y 
    int main(void) { 
        int i = -1; 
        int i2 = -2; 
        printf("%d",ALPHA(i,i2)); 
        return 0; 
    }
  • the program outputs -3
  • the program outputs -1
  • the program outputs -2
  • the program outputs 0

10. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	ALPHA(x,y)	x+y 
    int main(void) { 
        int i = -1; 
        int i2 = -2; 
        printf("%d",-ALPHA(i,i2)); 
        return 0; 
    }
  • the program outputs 0
  • the program outputs -3
  • the program outputs -2
  • the program outputs -1

11. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define A(x) 	((x)?-1:0) 
    int main(void) { 
        int i = 2; 
        int i2 = A(i) * i; 
        printf("%d",i2); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -2
  • the program outputs 0
  • the program outputs -3

12. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define A(x) 	((x)?-1:0) 
    #define B(a)	!(a) 
    int main(void) { 
        int i = 2; 
        int i2 = A(B(i)); 
        printf("%d",i2); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -3
  • the program outputs -2
  • the program outputs 0

13. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define A(x) 	#x 
    int main(void) { 
        int i = -1; 
        char *s = A(i); 
        i = -(s[0] == 'i'); 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs -3
  • the program outputs -1
  • the program outputs 0

14. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	X 	1 
    #define Y	2 

    int main(void) { 
        int i = 
    #if X<<Y > 0 
        -X 
    #else 
        -Y 
    #endif 
        ; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs 0
  • the program outputs -2
  • the program outputs -3
  • the program outputs -1

15. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define	X 	1 
    #define Y	2 

    int main(void) { 
        int i = 
    #if X>>Y > 0 
        -X 
    #else 
        -Y 
    #endif 
        ; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs 0
  • the program outputs -1
  • the program outputs -3

16. What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int X = 1; 
    #define	X 1 
        int Y = X - 2; 
    #undef X 
        printf("%d",Y+X); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs -3
  • the program outputs 0
  • the program outputs -1

17. What happens if you try to compile and run this program?

    #include <stdio.h> 

    int main(void) { 
    #undef X 
        int X = 1; 
        int Y = X - 2; 
    #define	X -2 
        printf("%d",Y+X); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs 0
  • the program outputs -1
  • the program outputs -3

18. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define  A 
    #define  C 
    int main(void) { 
        int i = 
    #ifdef A 
    #ifdef B 
        -1 
    #else 
        -2 
    #endif 
    #else 
        -3 
    #endif 
        ; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -2
  • the program outputs -3
  • the program outputs -1
  • the program outputs 0

19. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define  A 
    #define  C 
    int main(void) { 
        int i = 
    #ifdef A 
    #ifdef C 
        -1 
    #else 
        -2 
    #endif 
    #else 
        -3 
    #endif 
        ; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -3
  • the program outputs 0
  • the program outputs -2

20. What happens if you try to compile and run this program?

    #include <stdio.h> 
    #define  B 
    #define  C 
    int main(void) { 
        int i = 
    #ifdef A 
    #ifdef C 
        -1 
    #else 
        -2 
    #endif 
    #else 
        -3 
    #endif 
        ; 
        printf("%d",i); 
        return 0; 
    }
  • the program outputs -1
  • the program outputs -2
  • the program outputs 0
  • the program outputs -3

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